0=-(6x^2)+96x-372

Solution for 0=-(6x^2)+96x-372 equation:

0=-(6x^2)+96x-372

We move all terms to the left:

0-(-(6x^2)+96x-372)=0

We add all the numbers together, and all the variables

-(-6x^2+96x-372)=0

We get rid of parentheses

6x^2-96x+372=0

a = 6; b = -96; c = +372;
Δ = b2-4ac
Δ = -962-4·6·372
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-12\sqrt{2}}{2*6}=\frac{96-12\sqrt{2}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+12\sqrt{2}}{2*6}=\frac{96+12\sqrt{2}}{12}
$